Concrete · Beams
RC T-beam flexure (flange in compression) calculator
Rectangular stress block in a T-section: neutral axis in the flange or web, moment capacity, ductility (ku) and minimum steel.
Standard: AS 3600 Cl 8.1 (rectangular stress block)
Inputs in the worked example
The live calculator starts with these values; change any of them and every result, check and diagram updates instantly.
| Input | Value | Unit |
|---|---|---|
| Effective flange width | 1200 | mm |
| Flange thickness | 150 | mm |
| Web width | 350 | mm |
| Overall depth | 700 | mm |
| Effective depth | 630 | mm |
| Tension steel | 3100 | mm² |
| f′c | N32 | MPa |
| fsy | 500 | MPa |
| Design moment M* | 750 | kNm |
Worked example — results
| Result | Value | Unit |
|---|---|---|
| α2 = 0.85 − 0.0015 f′c (≥ 0.67) | 0.802 | |
| γ = 0.97 − 0.0025 f′c (≥ 0.67) | 0.890 | |
| Tension force Ast fsy | 1,550 | kN |
| Flange capacity α2 f′c bef Ds | 4,620 | kN |
| Stress block in flange? | yes | |
| Overhang force when block in web | 0.000 | kN |
| Stress block depth γ ku d | 50.33 | mm |
| ku = a/(γ d) | 0.090 | |
| φ = 1.24 − 13ku/12 (0.65 … 0.85) | 0.850 | |
| Mu | 937.5 | kNm |
| φMu | 796.9 | kNm |
| Ast,min = 0.20 (D/d)² 0.6√f′c/fsy bw d (approx. for T-beams) | 369.6 | mm² |
- ✓ M* ≤ φMu
- ✓ Ductility ku ≤ 0.36
- ✓ Ast ≥ Ast,min
Method, formulas and assumptions
- α2 = 0.85 − 0.0015 f′c (≥ 0.67) = MAX(0.67,0.85-0.0015*32) = 0.802
- γ = 0.97 − 0.0025 f′c (≥ 0.67) = MAX(0.67,0.97-0.0025*32) = 0.89
- Tension force Ast fsy = 3100*500/1000 = 1550 kN
- Flange capacity α2 f′c bef Ds = 0.802*32*1200*150/1000 = 4619.5 kN
- Stress block in flange? = IF(1550<=4619.5,"yes","no (in web)") = yes
- Overhang force when block in web = IF(1550<=4619.5,0,0.802*32*(1200-350)*150/1000) = 0 kN
- Stress block depth γ ku d = IF(1550<=4619.5,1550*1000/(0.802*32*1200),(1550-0)*1000/(0.802*32*350)) = 50.33 mm
- ku = a/(γ d) = 50.33/(0.89*630) = 0.089763
- φ = 1.24 − 13ku/12 (0.65 … 0.85) = MIN(0.85,MAX(0.65,1.24-13*0.089763/12)) = 0.85
- Mu = IF(1550<=4619.5,1550*(630-50.33/2),0*(630-150/2)+(1550-0)*(630-50.33/2))/1000 = 937.49 kNm
- φMu = 0.85*937.49 = 796.87 kNm
- Ast,min = 0.20 (D/d)² 0.6√f′c/fsy bw d (approx. for T-beams) = 0.2*(700/630)^2*0.6*SQRT(32)/500*350*630 = 369.58 mm²
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For preliminary design and education. Check every result against the current standard and your own engineering judgement before use.