Concrete · Beams
Doubly reinforced RC beam calculator
Rectangular beam with compression steel: neutral axis by trial on compression-steel yield, capacity and ductility.
Standard: AS 3600 Cl 8.1 · strain compatibility for compression steel
Inputs in the worked example
The live calculator starts with these values; change any of them and every result, check and diagram updates instantly.
| Input | Value | Unit |
|---|---|---|
| Width | 350 | mm |
| Depth | 600 | mm |
| Effective depth | 540 | mm |
| Depth to compression steel | 60 | mm |
| Tension steel | 4000 | mm² |
| Compression steel | 1200 | mm² |
| f′c | N32 | MPa |
| fsy | 500 | MPa |
| Design moment | 750 | kNm |
Worked example — results
| Result | Value | Unit |
|---|---|---|
| α2 = 0.85 − 0.0015 f′c (≥ 0.67) | 0.802 | |
| γ = 0.97 − 0.0025 f′c (≥ 0.67) | 0.890 | |
| Assume Asc yields: ku from (Ast − Asc) fsy = α2 f′c b γ ku d | 0.324 | |
| Compression steel strain 0.003(1 − dc/(ku d)) | 0.002 | |
| Compression steel yields? | no: stress reduced | |
| Compression steel stress (first estimate) | 394.4 | MPa |
| ku iteration 1 | 0.354 | |
| fsc iteration 2 | 411.5 | MPa |
| ku iteration 2 | 0.349 | |
| fsc iteration 3 | 408.9 | MPa |
| ku (converged) | 0.350 | |
| Concrete force | 1,509 | kN |
| Mu = Cc(d − γkud/2) + Asc fsc (d − dc) | 923.8 | kNm |
| φ | 0.850 | |
| φMu | 785.2 | kNm |
- ✓ M* ≤ φMu
- ✓ ku ≤ 0.36
Method, formulas and assumptions
- α2 = 0.85 − 0.0015 f′c (≥ 0.67) = MAX(0.67,0.85-0.0015*32) = 0.802
- γ = 0.97 − 0.0025 f′c (≥ 0.67) = MAX(0.67,0.97-0.0025*32) = 0.89
- Assume Asc yields: ku from (Ast − Asc) fsy = α2 f′c b γ ku d = (4000-1200)*500/(0.802*32*350*0.89*540) = 0.3243
- Compression steel strain 0.003(1 − dc/(ku d)) = 0.003*(1-60/(0.3243*540)) = 0.0019722
- Compression steel yields? = IF(0.0019722*200000>=500,"yes","no: stress reduced") = no: stress reduced
- Compression steel stress (first estimate) = MIN(500,MAX(0,0.0019722*200000)) = 394.43 MPa
- ku iteration 1 = (4000*500-1200*394.43)/(0.802*32*350*0.89*540) = 0.35365
- fsc iteration 2 = MIN(500,MAX(0,0.003*(1-60/(0.35365*540))*200000)) = 411.49 MPa
- ku iteration 2 = (4000*500-1200*411.49)/(0.802*32*350*0.89*540) = 0.34891
- fsc iteration 3 = MIN(500,MAX(0,0.003*(1-60/(0.34891*540))*200000)) = 408.93 MPa
- ku (converged) = (4000*500-1200*408.93)/(0.802*32*350*0.89*540) = 0.34962
- Concrete force = 0.802*32*350*0.89*0.34962*540/1000 = 1509.3 kN
- Mu = Cc(d − γkud/2) + Asc fsc (d − dc) = (1509.3*(540-0.89*0.34962*540/2)+1200*408.93*(540-60)/1000)/1000 = 923.76 kNm
- φ = MIN(0.85,MAX(0.65,1.24-13*0.34962/12)) = 0.85
- φMu = 0.85*923.76 = 785.19 kNm
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For preliminary design and education. Check every result against the current standard and your own engineering judgement before use.